Answer:

−1−x

(x−1)(x+2)

2

<0

x+1

(x−1)(x+2)

2

>0

xϵ(−∞,−2)∪(−2,−1)∪(1,∞)

Step-by-step explanation:

breaking the equations, we get

x - 1 = 0

=> x = 1

similarly, we can see x = 2.

hence, we can say

x >1 and x < = 2