Answer:

Since ∣x∣=x and −x

Therefore, ∣x−1∣>=2 may be calculated as:

x−1>=2 and −(x−1)>=2

⇒x>=2+1 and −x+1>=2

⇒x>=3 and −x>=2−1

⇒x>=3 and −x>=1

⇒x>=3 and x<=−1

Therefore, x lies between (−∞,−1]∪[3,+∞).

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