Answer:
Step-by-step explanation:
log 1 +log 1 =0+0 =0 [tan 45 =1/cot45 =1 ]
log( tan 45 degree) + log (cot 45 degree) = 0
The given question is to find the value of log( tan 45 degree) + log (cot 45 degree). This can be calculated as shown below as:
Using the property of law as:
log (xy) = log x + log y
Thus,
log( tan 45 degree) + log (cot 45 degree) = log (tan 45° × cot 45° )
Also, using the trigonometric relation of angle in tan and the angle in cot as:
tan x = 1/ cot x
log (tan 45° × cot 45° ) = log 1
Also, log 1 = 0
So,
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Answers & Comments
Answer:
Step-by-step explanation:
log 1 +log 1 =0+0 =0 [tan 45 =1/cot45 =1 ]
Answer:
log( tan 45 degree) + log (cot 45 degree) = 0
Step-by-step explanation:
The given question is to find the value of log( tan 45 degree) + log (cot 45 degree). This can be calculated as shown below as:
Using the property of law as:
log (xy) = log x + log y
Thus,
log( tan 45 degree) + log (cot 45 degree) = log (tan 45° × cot 45° )
Also, using the trigonometric relation of angle in tan and the angle in cot as:
tan x = 1/ cot x
Thus,
log (tan 45° × cot 45° ) = log 1
Also, log 1 = 0
So,
log( tan 45 degree) + log (cot 45 degree) = 0