Answer:
∆ng = np − nr = 1 − 1 = 0 ∴ ∴ ΔH = ΔU + ΔnRT ∵ ∵ Δng = 0 ∴ ∆H = ∆U
Explanation:
For the given reaction,
[tex]\sf C + O_2 \longrightarrow CO_2[/tex]
We know that,
[tex]: \implies \sf \Delta n_g = n_p - n_r[/tex]
[tex]: \implies \sf \Delta n_g = 1 - 1 = 0[/tex]
Therefore,
[tex]\therefore \sf \Delta H = \Delta U + \Delta nRT[/tex]
[tex]\qquad \quad \sf (\Delta ng = 0)[/tex]
[tex]\sf \bigstar {\underline{\boxed{\bf Relation : \Delta H = \Delta U}}}[/tex]
Hence The relation between ∆H and ∆U for the given reaction is ∆H = ∆U.
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Answers & Comments
Answer:
∆ng = np − nr = 1 − 1 = 0 ∴ ∴ ΔH = ΔU + ΔnRT ∵ ∵ Δng = 0 ∴ ∆H = ∆U
Explanation:
Verified answer
Required Answer:-
For the given reaction,
[tex]\sf C + O_2 \longrightarrow CO_2[/tex]
We know that,
[tex]: \implies \sf \Delta n_g = n_p - n_r[/tex]
[tex]: \implies \sf \Delta n_g = 1 - 1 = 0[/tex]
Therefore,
[tex]\therefore \sf \Delta H = \Delta U + \Delta nRT[/tex]
[tex]\qquad \quad \sf (\Delta ng = 0)[/tex]
[tex]\sf \bigstar {\underline{\boxed{\bf Relation : \Delta H = \Delta U}}}[/tex]
Hence The relation between ∆H and ∆U for the given reaction is ∆H = ∆U.