Answer:

Solution given:

1:(a,b)=(-2,2)

here

slope[m]=-co ordinate of x/co ordinate of y=-(-2/2)=1

we have equation of a single line is

y-b=m(x-a)

substituting value

y-2=1(x+2)

y-2=x+2

-x+y=2+2

x-y=-4 is a required equation.

2:

2.a= 4 b=-3

(a,b)=(4,-3)

slope[m]=-a/b=-4/-3=4/3

now

we have equation of a single line is

y-b=m(x-a)

substituting value

y+3=4/3*(x-4)

doing crisscrossed multiplication

3(y+3)=4(x-4)

3y+9=4x-16

-4x+3y=-16-9

4x-3y=25 is a required equation.