Answer:
[tex]11r + 15 = 2r^2 \\ 2r^2 - 11r - 15 \\ a = 2 \\ b = - 11 \\ c = - 15 \\ formula \: \: b^2 - 4ac \\ - 112 ^2 - 4(2)( - 15) \\ - 121 + 120\\ - 1[/tex]
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Answer:
[tex]11r + 15 = 2r^2 \\ 2r^2 - 11r - 15 \\ a = 2 \\ b = - 11 \\ c = - 15 \\ formula \: \: b^2 - 4ac \\ - 112 ^2 - 4(2)( - 15) \\ - 121 + 120\\ - 1[/tex]