Answer:

2

H

2

O

2

(

l

)

⇌

2

H

2

O

(

l

)

+

O

2

(

g

)

Explanation:

This is in fact a disproportionation reaction in that oxygen in peroxide (

−

I

oxidation state) has given water (

−

I

I

oxidation state for oxygen) and zerovalent oxygen gas (

0

oxidation state for oxygen).

Often a  

M

n

2

+

salt is added to catalyze this reaction.

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