// determine the starting number for the current row
int num = (i <= 3) ? (5 - 2 * i) : (3 - 2 * (i - 3));
// loop through the columns of the pattern
for (int j = 1; j <= 3; j++) {
// print the current number
System.out.print(num + " ");
// increment the number by 2
num += 2;
}
// move to the next line
System.out.println();
}
}
}
Explanation:
This solution uses two nested for loops to iterate through the rows and columns of the pattern. The starting number for each row is determined based on the row index, and the numbers in each column are incremented by 2. The numbers are printed to the console using the System.out.print method, and a new line is added after each row using the System.out.println method.
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Verified answer
Answer:
public class Pattern {
public static void main(String[] args) {
// loop through the rows of the pattern
for (int i = 1; i <= 5; i++) {
// determine the starting number for the current row
int num = (i <= 3) ? (5 - 2 * i) : (3 - 2 * (i - 3));
// loop through the columns of the pattern
for (int j = 1; j <= 3; j++) {
// print the current number
System.out.print(num + " ");
// increment the number by 2
num += 2;
}
// move to the next line
System.out.println();
}
}
}
Explanation:
This solution uses two nested for loops to iterate through the rows and columns of the pattern. The starting number for each row is determined based on the row index, and the numbers in each column are incremented by 2. The numbers are printed to the console using the System.out.print method, and a new line is added after each row using the System.out.println method.