Explanation:

1.) Convert 8.25 x 10¹⁸ CH₂O molecules to moles: First, determine the molar mass of CH₂O. The atomic weights are: C = 12.01 g/mol, H = 1.01 g/mol, and O = 16.00 g/mol. The molar mass of CH₂O is therefore 12.01 + (2 x 1.01) + 16.00 = 30.03 g/mol. To convert the number of molecules to moles, divide the number of molecules by the conversion factor, which is Avogadro's constant (6.022 x 10^23 molecules/mol). 8.25 x 10¹⁸ CH₂O molecules / (6.022 x 10^23 molecules/mol) = 1.37 x 10^-5 moles CH₂O

2.) Convert 8.18 moles of H in NH₃ to grams: First, determine the molar mass of NH₃. The atomic weights are: N = 14.01 g/mol, and H = 1.01 g/mol. The molar mass of NH₃ is therefore 14.01 + (3 x 1.01) = 17.04 g/mol. To convert moles to grams, multiply the number of moles by the molar mass. 8.18 moles NH₃ x 17.04 g/mol = 139.4 g NH₃

3.) Convert 3.67 moles of Zn(OH)₂ to grams: First, determine the molar mass of Zn(OH)₂. The atomic weights are: Zn = 65.38 g/mol, O = 16.00 g/mol, and H = 1.01 g/mol. The molar mass of Zn(OH)₂ is therefore 65.38 + (2 x 16.00) + (2 x 1.01) = 97.39 g/mol. To convert moles to grams, multiply the number of moles by the molar mass. 3.67 moles Zn(OH)₂ x 97.39 g/mol = 358.5 g Zn(OH)₂

4.) Convert 323 g of CBr₄ to moles of CBr₄: First, determine the molar mass of CBr₄. The atomic weights are: C = 12.01 g/mol, and Br = 79.90 g/mol. The molar mass of CBr₄ is therefore 12.01 + (4 x 79.90) = 350.8 g/mol. To convert grams to moles, divide the number of grams by the molar mass. 323 g CBr₄ / 350.8 g/mol = 0.92 moles CBr₄ 5.) Convert 12.5 g C₂H₆O to moles of C₂H₆O: First, determine the molar mass of C₂H₆O. The atomic weights are: C = 12.01 g/mol, H = 1.01 g/mol, and O = 16.00 g/mol. The molar mass of C₂H₆O is therefore (2 x 12.01) + (6 x 1.01) + 16.00 = 46.07 g/mol. To convert grams to moles, divide the number

5.) To convert grams to moles, divide the number of grams by the molar mass. 12.5 g C₂H₆O / 46.07 g/mol = 0.27 moles C₂H₆O