[tex]\underline{ \large{ \tt Required \: \: Answer:}}[/tex]

Electrolysis of fused lead bromide :

✧ Reaction at Anode : [tex] \sf{Br }^{1-} - 1 \: \overline{e} \longrightarrow Br [/tex]

[tex]\implies\sf{Br } + Br \longrightarrow Br _2 \: (reddish \: fumes \: of \: bromine \: gas)[/tex]

✧ Nature of Current : DC (Direct Current)

✧ Reaction at Cathode : [tex] \sf{Pb }^{2 + } + 2 \: \overline{e}\longrightarrow Pb \: (silvery \: grey \: deposits \: of \: lead)[/tex]

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Verified answer

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Molten lead bromide, PbBr 2(l), is an electrolyte. During electrolysis: Pb 2+ ions gain electrons at the cathode and become Pb atoms. Br - ions lose electrons at the anode and become Br atoms, which pair up to form Br 2 molecules