Note: There are total 3 attachments.
Answer:
(i) p(x) = x + 5
p(x) = 0
⇒ x + 5 = 0
⇒ x = -5
Therefore, -5 is the zero of p(x).
(ii) p(x) = x - 5
⇒ x - 5 = 0
⇒ x = 5
Therefore, 5 is the zero of p(x).
(iii) p(x) = 2x + 5
⇒ 2x + 5 = 0
⇒ 2x = -5
⇒ x = -5/2
Therefore, -5/2 is the zero of p(x).
(iv) p(x) = 3x - 2
⇒ 3x - 2 = 0
⇒ 3x = 2
⇒ x = 2/3
Therefore, 2/3 is the zero of p(x).
(v) p(x) = 3x
⇒ 3x = 0
⇒ x = 0
Therefore, 0 is the zero of p(x).
(vi) p(x) = ax, a ≠ 0
⇒ ax = 0
(vii) p(x) = cx + d, c ≠ 0, c, d are real numbers.
⇒ cx + d = 0
⇒ cx = -d
⇒ x = -d/c
Therefore, -d/c is the zero of p(x).
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Answers & Comments
Verified answer
Note: There are total 3 attachments.
Answer:
(i) p(x) = x + 5
p(x) = 0
⇒ x + 5 = 0
⇒ x = -5
Therefore, -5 is the zero of p(x).
(ii) p(x) = x - 5
p(x) = 0
⇒ x - 5 = 0
⇒ x = 5
Therefore, 5 is the zero of p(x).
(iii) p(x) = 2x + 5
p(x) = 0
⇒ 2x + 5 = 0
⇒ 2x = -5
⇒ x = -5/2
Therefore, -5/2 is the zero of p(x).
(iv) p(x) = 3x - 2
p(x) = 0
⇒ 3x - 2 = 0
⇒ 3x = 2
⇒ x = 2/3
Therefore, 2/3 is the zero of p(x).
(v) p(x) = 3x
p(x) = 0
⇒ 3x = 0
⇒ x = 0
Therefore, 0 is the zero of p(x).
(vi) p(x) = ax, a ≠ 0
p(x) = 0
⇒ ax = 0
⇒ x = 0
Therefore, 0 is the zero of p(x).
(vii) p(x) = cx + d, c ≠ 0, c, d are real numbers.
p(x) = 0
⇒ cx + d = 0
⇒ cx = -d
⇒ x = -d/c
Therefore, -d/c is the zero of p(x).
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