RATE of Change of MOMENTUM is DIRECTLY Propotional to the FORCE Applied Externally.
F α dp/dt ; p is the momentum
F = ma
IF THE FORCE ACTING "F" =0
0= m*a
MASS "m" IS CONSTANT
0=m*0
Thus it implies that:
F(B on A)=(dv/dt)m
By ADDing the both Forces ;
F(A on B) + F(B on A)= (dv/dt)m + (dv/dt)m
= (dv/dt) (m+m)
With no External Force the ACCELARATION =0 ( or ) the VELOCITY IS CONSTANT.
=> (dv/dt) = 0
F(A on B)+ F(A on B) = 0*m
F(A on B )= -F(A on B)
Thus the FIRST LAW OF MOTION IS CLEAR THAT ":
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
SECOND LAW OF MOTION:
RATE of Change of MOMENTUM is DIRECTLY Propotional to the FORCE Applied Externally.
F α dp/dt ; p is the momentum
F = ma
IF THE FORCE ACTING "F" =0
0= m*a
MASS "m" IS CONSTANT
0=m*0
Thus it implies that:
" AN BODY TENDS TO BE IN REST OR MOTION UNTILL AN EXTERNAL FORCE ACTS ON IT" .
F(B on A)=(dv/dt)m
By ADDing the both Forces ;
F(A on B) + F(B on A)= (dv/dt)m + (dv/dt)m
= (dv/dt) (m+m)
With no External Force the ACCELARATION =0 ( or ) the VELOCITY IS CONSTANT.
=> (dv/dt) = 0
F(A on B)+ F(A on B) = 0*m
F(A on B )= -F(A on B)
Thus the FIRST LAW OF MOTION IS CLEAR THAT ":
" Every action has an equal and opposite reaction".