Since the distance of each point on a plane passing through the centre of the electric dipole and perpendicular to the axis of the electric dipole is equal, the potential throughout the plane is zero. Hence it is one possible equipotential surface.
Explanation:
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Since the distance of each point on a plane passing through the centre of the electric dipole and perpendicular to the axis of the electric dipole is equal, the potential throughout the plane is zero. Hence it is one possible equipotential surface.
Explanation:
I hope it helps