Thiosulfate reacts differently with iodide and bromine due to their different redox potentials. Iodide has a lower redox potential than thiosulfate, which means that it can be easily oxidized by thiosulfate. In contrast, bromine has a higher redox potential than thiosulfate, which means that it is a stronger oxidizing agent than thiosulfate. Therefore, when thiosulfate reacts with iodide, it acts as a reducing agent and reduces iodide to iodine. When thiosulfate reacts with bromine, it acts as an oxidizing agent and is oxidized by bromine to form sulfate ions and bromide ions. The different redox potentials of iodide and bromine result in different reactions with thiosulfate.
Iodine oxidises S2O32− to S4O62− in which S has low oxidation state +2. 5 but bromine oxidises S2O32− to SO42− in which sulphurs has higher oxidation state +6. So, Bromine oxidises more and therefore it is stronger oxidising agent than iodine
Answers & Comments
Answer:
Thiosulfate reacts differently with iodide and bromine due to their different redox potentials. Iodide has a lower redox potential than thiosulfate, which means that it can be easily oxidized by thiosulfate. In contrast, bromine has a higher redox potential than thiosulfate, which means that it is a stronger oxidizing agent than thiosulfate. Therefore, when thiosulfate reacts with iodide, it acts as a reducing agent and reduces iodide to iodine. When thiosulfate reacts with bromine, it acts as an oxidizing agent and is oxidized by bromine to form sulfate ions and bromide ions. The different redox potentials of iodide and bromine result in different reactions with thiosulfate.
Explanation:
Iodine oxidises S2O32− to S4O62− in which S has low oxidation state +2. 5 but bromine oxidises S2O32− to SO42− in which sulphurs has higher oxidation state +6. So, Bromine oxidises more and therefore it is stronger oxidising agent than iodine