Answer:

What is the probability the player makes his first three free throws?

P(3 Free Throws Made) = P(One Free Throw Made AND One Free Throw Made AND One Free Throw Made)

P(3 Free Throws Made) = P(One Free Throw Made) * P(One Free Throw Made) * P(One Free Throw Made)

Note: this equation is possible since the events are independent.

P(3 Free Throws Made) = (7/10) * (7/10) * (7/10)

P(3 Free Throws Made) = (7*7*7)/(10*10*10)

P(3 Free Throws Made) = 343/1000

P(3 Free Throws Made) = 0.343

So the probability is 343/1000 or 0.343 (which is a 34.3% chance) to make all 3 free throws.

Note: In real life, these events are likely to be dependent. Eg, say the player misses the first two. If this happens, his/her confidence may be lowered which may contribute to missing the third one (ie also contributing to lowering the probability).