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There is a heap of blocks. Anil makes seperate heaps of 28 blocks from them. Shilpa makes seperate heaps of 32 blocks from the same heap. Nitin makes seperate heaps of 42 blocks. Each of them finds that 5 blocks are left after making the seperate heaps. What is the smallest possible numbers of blocks in the heap?
[Note: The required number of blocks=(LCM of 28,32,42+5]
There is a heap of blocks. Anil makes seperate heaps of 28 blocks from them. Shilpa makes seperate heaps of 32 blocks from the same heap. Nitin makes seperate heaps of 42 blocks. Each of them finds that 5 blocks are left after making the seperate heaps. What is the smallest possible numbers of blocks in the heap?
[Note: The required number of blocks=(LCM of 28,32,42+5]
Answers & Comments
Verified answer
Answer:
To find the smallest possible number of blocks in the heap, we need to calculate the least common multiple (LCM) of 28, 32, and 42, and then add 5 to the result.
First, let's calculate the LCM of 28, 32, and 42:
LCM(28, 32, 42) = LCM(LCM(28, 32), 42)
Now, calculate LCM(28, 32):
LCM(28, 32) = 224
Now, calculate LCM(224, 42):
LCM(224, 42) = 1344
Finally, add 5 to the LCM:
1344 + 5 = 1349
So, the smallest possible number of blocks in the heap is 1349.
Step-by-step explanation:
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Answer: 677
Step-by-step explanation:
given ,
let's find out LCM of 28 , 32 & 42
equation ANIL WANTS 28A + 5
SHILPA WANTS 32B + 5
NITIN WANTS 42C + 5
YOU NOTICE 5 IS COMMON IN ALL FORMATES SO 5 IS COMMON
HENCE TOTAL NO. of blocks be = x
REST IS 5
SO FIND LCM ....{ 28 ,32 , 42 } = 2 X 2 X 2 X 2 X 2 X 3 X 7 = 672
AND WE GET 672
TOTAL NO. OF blocks = 672 + 5 = 677
the smallest total no. block in the heaps = 677
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