Answer:
Let ABC be the triangle A(5,−2),B(6,4),C(7,−2)
By distance formula
AB=(5−6)2+(−2−4)2=(−1)2+(−6)237
BC=(6−7)2+(4−(−2)2=(−1)2+(6)2=37
CA=(7−5)2+(−2−(−2))2=(2)2+0=2
Since AB=BC=37
Hence (5,−2),(6,4) & (7,−2) are vertices of
IDONTKNOW
Explanation:
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Answer:
Let ABC be the triangle A(5,−2),B(6,4),C(7,−2)
By distance formula
AB=(5−6)2+(−2−4)2=(−1)2+(−6)237
BC=(6−7)2+(4−(−2)2=(−1)2+(6)2=37
CA=(7−5)2+(−2−(−2))2=(2)2+0=2
Since AB=BC=37
Hence (5,−2),(6,4) & (7,−2) are vertices of
Answer:
IDONTKNOW
Explanation: