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Answers & Comments
sahilyallur
Both the questions can be solved by Pythagoras theorem. 1)) height of the ladder=17m base=8m we should find the height of the wall. . let us assume it as triangle ABC. AB is the height of wall=? BC is the base=8m and AC is the height of the ladder=17m By Pythagoras, AC^2=AB^2+BC^2. we need to find AB,we will exchange the terms. AB^2=AC^2 - BC^2. AB^2=(17)^2 - (8)^2 AB^2= 289 - 64 AB^2= 225 AB=√225 AB=15m. therefore, height of the wall is 15m..
2)) similarly just like the first question. height of the ladder=AC=25m height of the wall=AB=20m base =BC=? by Pythagoras, AC^2=AB^2 + BC^2 AC^2 - AB^2 =BC^2 625- 400=BC^2 225=BC^2 BC=√225 BC=15m. therefore, base =15m.
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Answers & Comments
1)) height of the ladder=17m
base=8m
we should find the height of the wall.
. let us assume it as triangle ABC.
AB is the height of wall=?
BC is the base=8m
and AC is the height of the ladder=17m
By Pythagoras,
AC^2=AB^2+BC^2.
we need to find AB,we will exchange the terms.
AB^2=AC^2 - BC^2.
AB^2=(17)^2 - (8)^2
AB^2= 289 - 64
AB^2= 225
AB=√225
AB=15m.
therefore, height of the wall is 15m..
2)) similarly just like the first question.
height of the ladder=AC=25m
height of the wall=AB=20m
base =BC=?
by Pythagoras,
AC^2=AB^2 + BC^2
AC^2 - AB^2 =BC^2
625- 400=BC^2
225=BC^2
BC=√225
BC=15m.
therefore, base =15m.
HOPE,IT WILL BE USEFUL TO YOU .IF IT IS PLEASE MARK ME AS THE BRAINLIEST.
THANK YOU
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