Answer:
Correct option is
A
△ABC and △DEF in which : BC=EF, AC=DF and ∠C=∠F
C
△ABC and △LMN in which : ∠A=∠L=90
0
, AB=LM, ∠C=40
and ∠M=50
From Option A,
Given: △ABC and △DEF
BC=EF
AC=DF
∠C=∠F
Thus, △ABC≅△DEF (SAS rule)
From Option C,
In △ABC,
Sum of angles = 180
∠A+∠B+∠C=180
90+∠B+40=180
∠B=50
∘
Given, △ABC and △LMN,
∠A=∠L=90
AB=LM
∠B=∠M=50
Thus, △ABC≅△LMN (ASA rule)
Step-by-step explanation:
#hope it help
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Answers & Comments
Answer:
Correct option is
A
△ABC and △DEF in which : BC=EF, AC=DF and ∠C=∠F
C
△ABC and △LMN in which : ∠A=∠L=90
0
, AB=LM, ∠C=40
0
and ∠M=50
0
From Option A,
Given: △ABC and △DEF
BC=EF
AC=DF
∠C=∠F
Thus, △ABC≅△DEF (SAS rule)
From Option C,
In △ABC,
Sum of angles = 180
∠A+∠B+∠C=180
90+∠B+40=180
∠B=50
∘
Given, △ABC and △LMN,
∠A=∠L=90
∘
AB=LM
∠B=∠M=50
∘
Thus, △ABC≅△LMN (ASA rule)
Step-by-step explanation:
#hope it help