Trinomials in the form x2 + bx + c can often be factored as the product of two binomials. Remember that a binomial is simply a two-term polynomial. Let’s start by reviewing what happens when two binomials, such as (x + 2) and (x + 5), are multiplied.
Example
Problem
Multiply (x + 2)(x + 5).
(x + 2)(x + 5)
Use the FOIL method to multiply binomials.
x2 + 5x + 2x +10
Then combine like terms 2x and 5x.
Answer
x2 + 7x +10
Factoring is the reverse of multiplying. So let’s go in reverse and factor the trinomial x2 + 7x + 10. The individual terms x2, 7x, and 10 share no common factors. So look at rewriting x2 + 7x + 10 as x2 + 5x + 2x + 10.
And, you can group pairs of factors: (x2 + 5x) + (2x + 10)
Factor each pair: x(x + 5) + 2(x + 5)
Then factor out the common factor x + 5: (x + 5)(x + 2)
Answers & Comments
Answer:
A
Step-by-step explanation:
Trinomials in the form x2 + bx + c can often be factored as the product of two binomials. Remember that a binomial is simply a two-term polynomial. Let’s start by reviewing what happens when two binomials, such as (x + 2) and (x + 5), are multiplied.
Example
Problem
Multiply (x + 2)(x + 5).
(x + 2)(x + 5)
Use the FOIL method to multiply binomials.
x2 + 5x + 2x +10
Then combine like terms 2x and 5x.
Answer
x2 + 7x +10
Factoring is the reverse of multiplying. So let’s go in reverse and factor the trinomial x2 + 7x + 10. The individual terms x2, 7x, and 10 share no common factors. So look at rewriting x2 + 7x + 10 as x2 + 5x + 2x + 10.
And, you can group pairs of factors: (x2 + 5x) + (2x + 10)
Factor each pair: x(x + 5) + 2(x + 5)
Then factor out the common factor x + 5: (x + 5)(x + 2)