D. (0,5)
3x + 4y > 7
write the inequality:
3(0) + 4(5) > 7
substitute 0 for x and 5 for y:
3 × 0 + 4 × 5 > 7
multiply the numbers:
0 + 20 > 7
remove the zero:
20 > 7
20 is greater than 7. so (0,5) is the solution to an inequality.
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D. (0,5)
3x + 4y > 7
write the inequality:
3(0) + 4(5) > 7
substitute 0 for x and 5 for y:
3 × 0 + 4 × 5 > 7
multiply the numbers:
0 + 20 > 7
remove the zero:
20 > 7
20 is greater than 7. so (0,5) is the solution to an inequality.