Explanation:

(d) It forms diethylthioether on heating with alcoholic KSH.

C2H5Br (ethyl bromide) can undergo a Williamson ether synthesis reaction with alcoholic potassium sulfide (KSH) to form diethylthioether. This reaction involves the substitution of the bromine atom with the thiolate ion (-SCH2CH3), resulting in the formation of a thioether compound.

Answer:

(c) It gives C2H5OH on boiling with alcoholic potash.

Explanation:

When C2H5Br, which is ethyl bromide, is heated with alcoholic potash (KOH dissolved in alcohol), it undergoes a reaction called hydrolysis. In this reaction, the C2H5Br molecule reacts with the OH- ion from the alcoholic potash to form C2H5OH, which is ethyl alcohol, also known as ethanol.

This reaction can be represented by the following equation:

C2H5Br + KOH → C2H5OH + KBr

The hydrolysis of ethyl bromide with alcoholic potash is an example of a nucleophilic substitution reaction. In this reaction, the OH- ion acts as a nucleophile, attacking the carbon atom bonded to the bromine atom in the ethyl bromide molecule. This leads to the displacement of the bromine atom by the hydroxyl group, resulting in the formation of ethyl alcohol.

It is important to note that option (a) is incorrect because the reaction of C2H5Br with metallic Na does not give ethane. Option (b) is incorrect because the reaction of C2H5Br with the aqueous solution of AgNO2 does not produce nitroethane. Option (d) is incorrect because the reaction of C2H5Br with alcoholic KSH does not form diethylthioether.

Therefore, the correct statement for C2H5Br is (c) It gives C2H5OH on boiling with alcoholic potash.

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