May choices yan eh
#CarryOnLearning
Answer:
Step-by-step explanation:
2p²+5p-1=0
solve the quadratic equetion .ax²+bxc=0
---------------------------
2a
p=-5±√5²-4x2x2x(-1)
-------------------------------
2(2)
evaluate the power
p=-5±√25-4x2x(-1)
---------—–—————
next is add the no.
p= -5±√25-4x2x(-1)
-----------------------------
p=-5±√33
----------------
4
p= -5+√33
---------------
p=-5-√33
the equetion has 2 solution
p¹=-5-√33,p²=-5+√33
--------------, ----------------
4 4
alternate form:(P¹≈2.68614,P²≈0.186141)
thats the final answer
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May choices yan eh
The Answers Are:
#CarryOnLearning
Answer:
Step-by-step explanation:
2p²+5p-1=0
solve the quadratic equetion .ax²+bxc=0
---------------------------
2a
p=-5±√5²-4x2x2x(-1)
-------------------------------
2(2)
evaluate the power
p=-5±√25-4x2x(-1)
---------—–—————
2(2)
next is add the no.
p= -5±√25-4x2x(-1)
-----------------------------
2(2)
p=-5±√33
----------------
4
p= -5+√33
---------------
4
p=-5-√33
---------------
4
the equetion has 2 solution
p¹=-5-√33,p²=-5+√33
--------------, ----------------
4 4
alternate form:(P¹≈2.68614,P²≈0.186141)
thats the final answer