Answer:

The sum of a two digit number and the number obtained by reversing the order of the digit is 165. If the digits are differ by 3, find the original number? 96+69=165 & 9–6=3.

Answer:

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Step-by-step explanation:

Let the digits of the number be x and y

(10x+y)+(10y+x)=165 &. x-y=3

11x+11y=165

x+y=15

x-y=3

2x=18

x=9

y=15–9=6

Therefore the number is 96 //

96+69=165 & 9–6=3.

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