Answer:
Explanation:
CaCO3 →CaO+CO2 (g)
1mole CaO=1mole CaCO 3
Molar mass of CaO=56g/mol
Molar mass of CaCO 3 =100 g/mol
=>
[tex]Mass \: of \: CaCO 3 \: that \: produces \\ 4.48g \: of \: CaO = \frac{4.48 \times 100}{56} \: = 8g[/tex]
So, 8g is answer.
8g
\begin{gathered}Mass \: of \: CaCO 3 \: that \: produces \\ 4.48g \: of \: CaO = \frac{4.48 \times 100}{56} \: = 8g\end{gathered}
MassofCaCO3thatproduces
4.48gofCaO=
56
4.48×100
=8g
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Answers & Comments
Verified answer
Answer:
8g
Explanation:
CaCO3 →CaO+CO2 (g)
1mole CaO=1mole CaCO 3
Molar mass of CaO=56g/mol
Molar mass of CaCO 3 =100 g/mol
=>
[tex]Mass \: of \: CaCO 3 \: that \: produces \\ 4.48g \: of \: CaO = \frac{4.48 \times 100}{56} \: = 8g[/tex]
So, 8g is answer.
Explanation:
Answer:
8g
Explanation:
CaCO3 →CaO+CO2 (g)
1mole CaO=1mole CaCO 3
Molar mass of CaO=56g/mol
Molar mass of CaCO 3 =100 g/mol
=>
\begin{gathered}Mass \: of \: CaCO 3 \: that \: produces \\ 4.48g \: of \: CaO = \frac{4.48 \times 100}{56} \: = 8g\end{gathered}
MassofCaCO3thatproduces
4.48gofCaO=
56
4.48×100
=8g
So, 8g is answer.