There are two mirrors, mirrors are associated with the reflection of light rays, and the reflection of light follows a certain Snell's law which says that the angle of incidence and that of reflection are equal.
The first mirror(the one where the light ray strikes first) can be extended so that it touches the dotted line already drawn by the question maker.
Can you see a right-angled triangle forming at the place where you just extended the first mirror so that it now touches the normal of mirror 2?
In this right-angled triangle(say, triangle A) one angle is x, one is 90° and the last angle is 60°. Surprised? Nah, you wouldn't be.
This 60° came from mirror 1. If you drew a normal at the place where the ray strikes the mirror 1, you'd put the angle of incidence = angle of reflection at that place, even though they're unknown to us.
We can calculate them, well.
Normal makes 90° with the mirror and the angle between the incident ray and the mirror is 60°, which makes the angle of incidence and reflection equal to 30°.
Since the sum of all angles in a straight line = 180°, the angle in triangle A, the angle between the reflected ray and the mirror comes out to be 60°.
In triangle A,
the sum of all angles in a triangle = 180°
==> 90 + x + 60 = 180
==> x = 30°
So the answer is 30°.
How have you been? I like apples, and don't know most of the other fruits. Comment if you don't get this answer, I'll try and answer it with some diagrams then. :
Answers & Comments
Answer:
30°
Explanation:
do normal and alternate u will come to know
Answer:
x would be 30°
There are two mirrors, mirrors are associated with the reflection of light rays, and the reflection of light follows a certain Snell's law which says that the angle of incidence and that of reflection are equal.
The first mirror(the one where the light ray strikes first) can be extended so that it touches the dotted line already drawn by the question maker.
Can you see a right-angled triangle forming at the place where you just extended the first mirror so that it now touches the normal of mirror 2?
In this right-angled triangle(say, triangle A) one angle is x, one is 90° and the last angle is 60°. Surprised? Nah, you wouldn't be.
This 60° came from mirror 1. If you drew a normal at the place where the ray strikes the mirror 1, you'd put the angle of incidence = angle of reflection at that place, even though they're unknown to us.
We can calculate them, well.
Normal makes 90° with the mirror and the angle between the incident ray and the mirror is 60°, which makes the angle of incidence and reflection equal to 30°.
Since the sum of all angles in a straight line = 180°, the angle in triangle A, the angle between the reflected ray and the mirror comes out to be 60°.
In triangle A,
the sum of all angles in a triangle = 180°
==> 90 + x + 60 = 180
==> x = 30°
So the answer is 30°.
How have you been? I like apples, and don't know most of the other fruits. Comment if you don't get this answer, I'll try and answer it with some diagrams then. :