The balls velocity below the point of release will be faster than the initial speed = 0 and reach the maximum before it hits the ground
Further explanation
The motion of a ball dropped at a point is an example of free fall motion
Free fall motion is included in uniformly accelerated motion with constant acceleration. Its acceleration is influenced by Earth's gravity of g (g = 10 m / s²)
In this motion the equation applies
vt = gt
h = 1/2 gt²
h = distance / height
g = acceleration due to gravity
t = time
vt = speed when t seconds
The initial speed of the ball when released is 0
Free fall motion is said to have a constant acceleration so that the change in velocity at a certain time interval is constant
[tex]\rm a=\dfrac{\Delta v }{\Delta t }[/tex]
If we make a graph of accelerationvs time, the line obtained is a straight line parallel to the t axis
In this a vs t graph, the area under the graph is the change in velocity of Δv (v-vo)
So it can be concluded that within a certain time interval, the velocity of the ball will increase, and reach the maximum when it will hit the ground exactly
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The velocity of the ball just before it hits the ground
When a ball falls below the point of releasing its velocity increases. The falling of the ball is controlled by the two forces, the drag force and acceleration due to gravity. The acceleration due to gravity accelerates the ball in the downward direction at the constant rate. The drag force slows the ball when it falls below and it is a function of velocity so when the velocity of the ball increases so the drag force also increases.
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Verified answer
Answer:
The balls velocity below the point of release will be faster than the initial speed = 0 and reach the maximum before it hits the ground
Further explanation
The motion of a ball dropped at a point is an example of free fall motion
Free fall motion is included in uniformly accelerated motion with constant acceleration. Its acceleration is influenced by Earth's gravity of g (g = 10 m / s²)
In this motion the equation applies
vt = gt
h = 1/2 gt²
h = distance / height
g = acceleration due to gravity
t = time
vt = speed when t seconds
The initial speed of the ball when released is 0
Free fall motion is said to have a constant acceleration so that the change in velocity at a certain time interval is constant
[tex]\rm a=\dfrac{\Delta v }{\Delta t }[/tex]
If we make a graph of acceleration vs time, the line obtained is a straight line parallel to the t axis
In this a vs t graph, the area under the graph is the change in velocity of Δv (v-vo)
So it can be concluded that within a certain time interval, the velocity of the ball will increase, and reach the maximum when it will hit the ground exactly
Learn more
The velocity of the ball just before it hits the ground
https://brainly.ph/question/519262
Answer:
The ball's velocity will increase
When a ball falls below the point of releasing its velocity increases. The falling of the ball is controlled by the two forces, the drag force and acceleration due to gravity. The acceleration due to gravity accelerates the ball in the downward direction at the constant rate. The drag force slows the ball when it falls below and it is a function of velocity so when the velocity of the ball increases so the drag force also increases.
Explanation:
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