hope it helps you
[tex]\huge\mathcal{\fcolorbox{yellow} {beige}{ \orange{ᏗᏁᏕᏇᏋᏒ}}}[/tex]
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[tex] \sf ¹²C \: is \: a \: staple \: isotrope \: of \: carbon. \: The \: atomic \: number \: of ¹²C \: is \: 6.[/tex]
[tex]{ \boxed{ \boxed{ \bold{Molar mass (mass of one mole) is 12 and 1 mole = 6.022 \times {10}^{23} }}}}[/tex]
[tex] \sf ∴6.022 \times {10}^{23}
atoms \: have \: mass = 12g[/tex]
[tex] \sf∴ 1 \: atom \: have \: mass = \dfrac{12}{6.022 \times {10}^{23} } = 1.993 \times {10}^{2 - 23} g[/tex]
[tex]{ \orange{ \sf \: mass \: of \: {}^{12} c \: is \: 1.993 \times {10}^{ - 23} g}}[/tex]
[tex]{ \orange {\sf \: hope \: it \: helps \: you}}[/tex]
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Answers & Comments
= 1.993 × 10- ²³ g. Q
this is your answer
hope it helps you
Verified answer
[tex]\huge\mathcal{\fcolorbox{yellow} {beige}{ \orange{ᏗᏁᏕᏇᏋᏒ}}}[/tex]
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[tex] \sf ¹²C \: is \: a \: staple \: isotrope \: of \: carbon. \: The \: atomic \: number \: of ¹²C \: is \: 6.[/tex]
[tex]{ \boxed{ \boxed{ \bold{Molar mass (mass of one mole) is 12 and 1 mole = 6.022 \times {10}^{23} }}}}[/tex]
[tex] \sf ∴6.022 \times {10}^{23}
atoms \: have \: mass = 12g[/tex]
[tex] \sf∴ 1 \: atom \: have \: mass = \dfrac{12}{6.022 \times {10}^{23} } = 1.993 \times {10}^{2 - 23} g[/tex]
[tex]{ \orange{ \sf \: mass \: of \: {}^{12} c \: is \: 1.993 \times {10}^{ - 23} g}}[/tex]
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[tex]{ \orange {\sf \: hope \: it \: helps \: you}}[/tex]