hense given no.of mole(n)=Mass of Al(m)/Molar mass of Al(M)
n=54gm/27gm per mol=2mol
No.of in 1mol=Avogadro'sno.=6.022*10 raised to23Hense no. Of atom in 2mols =2*6.022*10raised to 23.Hense 2 moles (n)ofMg mass is, atomic mass of Mg =24.3Molar mass of Mg(M) =24.3gm per molMass of Mg=n*M=2*24.3=48.6gm
Answers & Comments
1 mole of Mg contain 24 g
So 2 mole contain 48 g
Atomic mass of Al=27
hense Molar mass of Al(M)= 27 gm per mol
hense given no.of mole(n)=Mass of Al(m)/Molar mass of Al(M)
n=54gm/27gm per mol=2mol
No.of in 1mol=Avogadro'sno.=6.022*10 raised to23Hense no. Of atom in 2mols =2*6.022*10raised to 23.Hense 2 moles (n)ofMg mass is, atomic mass of Mg =24.3Molar mass of Mg(M) =24.3gm per molMass of Mg=n*M=2*24.3=48.6gm