What volume of a 2.5 M stock solution of acetic acid (HC2H3O2) is required to prepare 100.0 milliliters of a 0.50 M acetic acid solution?
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M1V1=M2V2
M1=initial molarity
V1=initial volume
M2=final molarity
V2=final volume
Therefore,according to the question
M1=2.5M
V1=?
M2=0.5M
V2=100ml
V1=(M2×V2)÷M1
V1=(0.5×100)÷2.5
V1=20ml
Therefore the final answer is 20ml