Answer:

Given:

for tank1

d = 4ft h = 7ft

V=Bh where B is the area of the base and his the height

B=pi*r^2=pi(d/2)^2=pi*d^2/4

B = [pi * (4) ^ 2] / 4 B = 4pi sq ft

V1=(4pi)(7)

V1=28pi or approximately 87.9646 cubic ft

for tank2

L = 1m

W = 2m h = 2m

V=Bh (base area times height)

B=L*W

B=1*2 B = 2sqm

V2=(2)(2) V2=4 cu. m

V1-(87.9646 ft^3)(1 m^3/(3.2808)^3 ft^3) = (approx.) 2.491 cu. m