Answer:
Use this equation
Q = mC
Δ
T
where
Q =
Heat
m =
Mass of sample
C =
Specific heat of sample (
4.186 J/g°C
for water)
ΔT =
Change in temperature
Q
=
50
g
×
4.186 J
°C
(
45.0
−
40.0
)
1046.5 J
≈
1.05 kJ
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Answers & Comments
Answer:
Use this equation
Q = mC
Δ
T
where
Q =
Heat
m =
Mass of sample
C =
Specific heat of sample (
4.186 J/g°C
for water)
ΔT =
Change in temperature
Q
=
50
g
×
4.186 J
g
°C
×
(
45.0
−
40.0
)
°C
=
1046.5 J
≈
1.05 kJ