Verified answer

SOLUTION:

The molar mass of HCl is 36.461 g/mol.

The volume of 1 mole of an ideal gas at STP is 22.414 L.

[tex]\begin{aligned} V & = \text{49.8 g HCl} \times \frac{\text{1 mol HCl}}{\text{36.461 g HCl}} \times \frac{\text{22.414 L}}{\text{1 mol HCl}} \\ & = \boxed{\text{30.6 L}} \end{aligned}[/tex]

Hence, the volume of 49.8 g of HCl at STP is 30.6 L.

[tex]\\[/tex]

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