Answer:

What is the vertex of the parabola of the quadratic function f(x) = (x-5)²+ 2?

a. (5,2)

b. (5,-2)

c. (-5,2)

d. (-5, -2)

f(x) = a(x-h)²+k

where V(h,k)

Given that: f(x) = (x-5)²+2

h = 5 , k = 2

we can see that Vertex is at (5,2)