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since(x+15)°and (2y+25)°are alternate angles.so the are equal x+15=2y+25 x-2y+15-25=0 x-2y-10=0. -(1) since 3y° and (2y+25) ° are also alternate angles so they are also equal . 3y=2y+25 3y-2y=25 y=25° now putting the value in eqn (1). x-2×25-10=0 x-50-10=0 x=60° so the value of x is 60° and y is 25°. thanks please mark me brainliest.
Answers & Comments
x+15=2y+25
x-2y+15-25=0
x-2y-10=0. -(1)
since 3y° and (2y+25) ° are also alternate angles
so they are also equal .
3y=2y+25
3y-2y=25
y=25°
now putting the value in eqn (1).
x-2×25-10=0
x-50-10=0
x=60°
so the value of x is 60° and y is 25°.
thanks
please mark me brainliest.