k=3
(3k-11)=(5k-3)+(3-1)(2k-13)
3k-11=5k-3+2(2k-13)
3k-11+5k-3+4k-26
3k-5k-4k= -3-26+11
-6k = -18
-6 -6
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Answers & Comments
k=3
(3k-11)=(5k-3)+(3-1)(2k-13)
3k-11=5k-3+2(2k-13)
3k-11+5k-3+4k-26
3k-5k-4k= -3-26+11
-6k = -18
-6 -6
k=3