Answer:
Sum of 10 multiples of 3 ,
a = 3,
d = 3,
n = 10,
S10 = ?,
To find S10 -
Sn = n/2 (2a + (n - 1) d )
= 10/2 (2 x 3 + (10 -1) 3)
= 5 (6 + 9 x 3)
= 5 (6 + 27)
= 5 x 33
= 165
Sum of first 10 multiples of 3 is 165
Step-by-step explanation:
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Answers & Comments
Answer:
Sum of 10 multiples of 3 ,
a = 3,
d = 3,
n = 10,
S10 = ?,
To find S10 -
Sn = n/2 (2a + (n - 1) d )
= 10/2 (2 x 3 + (10 -1) 3)
= 5 (6 + 9 x 3)
= 5 (6 + 27)
= 5 x 33
= 165
Sum of first 10 multiples of 3 is 165
Step-by-step explanation:
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