The pOH is the negative logarithm of the hydroxide-ion. The pOH is calculated by the formula:
pOH = - log ([])
The given is the molarity or the concentration of the hydrogen ion in moles per liter of 1.75M NaOH. We need to know the pOH.
NaOH is a strong base that dissociates completely in an aqueous solution that forms or sodium cation and or hydroxide ions. The dissociation chemical equation can be written as:
NaOH ⇒ +
Step 1: From the chemical equation, we can see that NaOH has a mole ratio of 1:1 to the or hydroxide ions. Hence,
1.75M NaOH = 1.75M
Step 2: We can directly substitute the given value to the pOH formula. Thus,
pOH = - log ([])
pOH = - log [(1.75 M])
pOH = -0.24
Therefore, the pOH of 1.75M NaOH is -0.24.
To learn more about calculating pOH, click the links below:
Answers & Comments
Answer:
pOH = -0.24
Explanation:
Calculating pOH
The pOH is the negative logarithm of the hydroxide-ion. The pOH is calculated by the formula:
pOH = - log ([
])
The given is the molarity or the concentration of the hydrogen ion in moles per liter of 1.75M NaOH. We need to know the pOH.
NaOH is a strong base that dissociates completely in an aqueous solution that forms
or sodium cation and
or hydroxide ions. The dissociation chemical equation can be written as:
NaOH ⇒
+
Step 1: From the chemical equation, we can see that NaOH has a mole ratio of 1:1 to the
or hydroxide ions. Hence,
1.75M NaOH = 1.75M
Step 2: We can directly substitute the given value to the pOH formula. Thus,
pOH = - log ([
])
pOH = - log [(1.75 M])
pOH = -0.24
Therefore, the pOH of 1.75M NaOH is -0.24.
To learn more about calculating pOH, click the links below:
pH and pOH: brainly.ph/question/1123233
pH and pOH: brainly.ph/question/2725941
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