Oxidation number (ON) or state simply tells the degree of oxidation of a species. The species may be an element, ion, compound or the elements/ ions in a compound.
For any compound, its overall oxidation number (ON) is assigned zero. The individual ON of each species is added up to give a total of zero.
In the case of the compound, potassium sulphate, K2SO4, the common ON of potassium, K is +1 & oxygen, O is -2. Now let the unknown ON of the sulphur, S be X.
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Answer:
In the case of the compound, potassium sulphate, K2SO4, the common ON of potassium, K is +1 & oxygen, O is -2.
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Oxidation number (ON) or state simply tells the degree of oxidation of a species. The species may be an element, ion, compound or the elements/ ions in a compound.
For any compound, its overall oxidation number (ON) is assigned zero. The individual ON of each species is added up to give a total of zero.
In the case of the compound, potassium sulphate, K2SO4, the common ON of potassium, K is +1 & oxygen, O is -2. Now let the unknown ON of the sulphur, S be X.
K2SO4 = 2(+1) + X + 4(-2) = 0
From this X = +6. ie, the ON of sulphur is +6