What is the minimum amount of pure alcohol that must be added to 10 liters of 30% alcohol solution to obtain a mixture that is at least 40% alcohol? (Show how to solve)
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10 + 30% + 40%
10 + 30% = 40%
40% + 40% = 80%
ᴀɴsᴡᴇʀ: 80%
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