What is the measure of a side of a square whose area is a (4x2+28x+49) square units?
a. 2x-7 b. 2x+7 c. x2+3 d. 2x2+72
a. 2x-7 b. 2x+7 c. x2+3 d. 2x2+72
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Answer:
b. 2x + 7
Given:
Area = 4x² + 28x + 49
Required:
s = ?
Solution:
A = s²
s² = 4x² + 28x + 49
s² = 4x² + 14x + 14x + 49
s² = (4x² + 14x) + (14x + 49)
s² = 2x(2x + 7) + 7(2x + 7)
s² = (2x + 7)(2x + 7)
s² = (2x + 7)²
s = 2x + 7
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Answer:
b. 2x + 7
Step-by-step explanation:
factor out 4x²+28x+49 using perfect square rule.
(2x+7)² = 4x²+28x+49