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An airplane lands with an initial velocity of 70.0 m/s and then accelerates opposite to the motion at 1.50 m/s2 for 40.0 s. What is its final velocity?
Strategy
First, we identify the knowns: v0=70m/s,a=−1.50m/s2,t=40sv0=70m/s,a=−1.50m/s2,t=40s.
Second, we identify the unknown; in this case, it is final velocity vfvf.
Last, we determine which equation to use. To do this we figure out which kinematic equation gives the unknown in terms of the knowns. We calculate the final velocity using Equation 3.12, v=v0+atv=v0+at.
Answers & Comments
Explanation:
Calculating Final Velocity
An airplane lands with an initial velocity of 70.0 m/s and then accelerates opposite to the motion at 1.50 m/s2 for 40.0 s. What is its final velocity?
Strategy
First, we identify the knowns: v0=70m/s,a=−1.50m/s2,t=40sv0=70m/s,a=−1.50m/s2,t=40s.
Second, we identify the unknown; in this case, it is final velocity vfvf.
Last, we determine which equation to use. To do this we figure out which kinematic equation gives the unknown in terms of the knowns. We calculate the final velocity using Equation 3.12, v=v0+atv=v0+at.
Solution
Substitute the known values and solve:
v=v0+at=70.0m/s+(−1.50m/s2)(40.0 s)=10.0 m/s.v=v0+at=70.0m/s+(−1.50m/s2)(40.0 s)=10.0 m/s.
Figure 3.19 is a sketch that shows the acceleration and velocity vectors.