PÒTASSIUM CHLORIDE

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Given:

K (Pòtassium) = 39.1 g

Cl (Chlorine) = 35.6 g

Answer & Solution:

\sf molar \: mass \times 5.24 \: molmolarmass×5.24mol

\sf = (39.1 \: g + 35.6 \: g)(5.24 \: mol)=(39.1g+35.6g)(5.24mol)

\sf = (74.7 \: g/mol)(5.24 \: mol)=(74.7g/mol)(5.24mol)

\sf = \boxed{ \sf 391.43 \: g}=

391.43g

↬ Hence, the mass of 5.24 mol of KCl is 391.43 g