Answer:

it's 9.8

Explanation:

because force is equal to G m×M/r×r

Verified answer

Answer:

Given

[tex] \bf \: Mass \:of \: the \: earth \: =M=6 \times 10^{24 } Kg \\ \bf \: Mass \: of \: the \: object \: = m = 1 kg \\ \bf \: Gravitational \: constant \: = G = 6.7 \times 10 ^{ -11} Nm^ 2 kg^{ -2}[/tex]

Distance between the earth's center and the object

=Radius of the earth

[tex] \bf \: =6.4 \times 10^ 6 m[/tex]

We know that

[tex] \bf \: Gravitational \: Force = \frac{GMm}{r ^ 2} \\ [/tex][tex] \sf= \frac{6.7 \times 10^{-11} \times 6 \times 10^{24} \times 1}{(6.4 \times 10^ 6 )^ 2} \\ \\ \sf = \frac{6.7 \times 6 \times 10^{ -11} \times 10^ {24 } \times 1}{(6.4)^ 2 \times 10^ 6 \times 2} \\ \\ \sf = \frac{40.2 \times 10^ {24-11}}{40.96 \times 10^ {12}} \\ \\ \sf = \frac{40.2 \times 10^ {13}}{40.96 \times 10^ {12}} \\ \\ \sf = \frac{40.2 \times 10^{ 13-12}}{40.96} \\ \\ \sf= \frac{40.2 \times 10}{40.96} \\ \\ \sf = \frac{402}{40.96} \\ \\ \sf= \frac{402 \times 100 }{4096} \\ \\ \sf = 9.81N \\ \bf \: Thus, \: force \: is \: 9.81 N[/tex]

Hope it helps :-D