What is the least number That is divisible by all the natural number from 1 to 10 and how
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First write the prime factorization of each number.
1=1. (one is not prime).
2=2
3=3
4=2 x 2
5=5
6=3 x 2
7=7
8=2 x2x 2
9 = 3 x 3
10 = 5 x 2
multiply the different primes the maximum number of times they occur in an example. So for the number 2, we see that 8 is 2 times 2 times 2 .This ensures the 2’s in 2, 4, 6, and 10 are “covered.” We don’t need to multiply by any more twos.
Continuing this process we obtain
(2x2x2)(3x3)(5)(7)=2520
Your answer is 2520
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we have to find What is the least number That is divisible by all the natural number from 1 to 10 and how
so no.from 1 to 10
=>1,2,3,4,5,6,7,8,9,10
now we have to find the lcm of these numbers
lets do it by prime factorsiation
1=1.
2=2
3=3
4=2 x 2
5=5
6=3 x 2
7=7
8=2 x2x 2
9 = 3 x 3
10 = 5 x 2
so now lcm
=> 2 x 2 x 2*3 x 3*5*7=2520
hence 2520 is the
the least number That is divisible by all the natural number from 1 to 10hope it helps u
:)