Answer:
n(a n b) = number divisible by both 7 and 11 (i.e. 77)
By using above formula
n(A ∪ B) = n(A) + n(B) - n(A ∩ B)
Number of positive integers below 1000, which are divisible by 7 or 11
n(A ∪ B) = 142 + 90 - 12
⇒ n(A ∪ B) = 220 ) 1000
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Answer:
n(a n b) = number divisible by both 7 and 11 (i.e. 77)
By using above formula
n(A ∪ B) = n(A) + n(B) - n(A ∩ B)
Number of positive integers below 1000, which are divisible by 7 or 11
n(A ∪ B) = 142 + 90 - 12
⇒ n(A ∪ B) = 220 ) 1000