What is the greatest value of N if the
different 4035-29N6 is divisible by 3 is?
A.4
B.2
C.7
D.6
different 4035-29N6 is divisible by 3 is?
A.4
B.2
C.7
D.6
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Step-by-step explanation:
4+0+3+5=12, 12 is divisible by 3
2+9+N+6=17+N so the N will be 4 thus 17+4=21
and 21 divisible by 3
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