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Answer:

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Force between the two small charged spheres is 6×10^−3N.

Explanation:

q1=2×10^7C

q2=3×10^7C

r=30cm(0.3m)

F=q1q2/4πε0r^2

Where, ε0= Permittivity of free space

1/4πε0=9×10^9Nm^2C^−2

F=2×10^7×3×10^7/9×10^9×(0.3)^2

F=6×10^-3N

Hence, force between the two small charged spheres is 6×10^−3N. The charges are of same nature. Hence, force between them will be repulsive.