Answer:
:)
Step-by-step explanation:
=[(5x)²-(1)²]+[1+5x]²
=(5x-1)(5x+1)+(1+5x)(1+5x)
take 1+5x common
=(1+5x)[(5x-1)+(5x+1)]
=(1+5x)(5x-1+5x+1)
=(1+5x)(10x).
so, factors of given eq are 10x & 1+5x.
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Answers & Comments
Answer:
:)
Step-by-step explanation:
=[(5x)²-(1)²]+[1+5x]²
=(5x-1)(5x+1)+(1+5x)(1+5x)
take 1+5x common
=(1+5x)[(5x-1)+(5x+1)]
=(1+5x)(5x-1+5x+1)
=(1+5x)(10x).
so, factors of given eq are 10x & 1+5x.