Answer:
Since both terms are perfect cubes, factor using the sum of cubes formula,
a³+b³=(a+b)(a²−ab+b²) where a=2a and b=b.27(2a+b)(4a²−2ab+b²)
27(2a+b)(4a²−2ab+b²)
Step-by-step explanation:
216a³+27b³
= 27(8a³+b³)
= (2a+b)(4a²−2ab+b²)
= 27(2a+b)(4a²−2ab+b²)
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Answers & Comments
Answer:
Since both terms are perfect cubes, factor using the sum of cubes formula,
a³+b³=(a+b)(a²−ab+b²) where a=2a and b=b.27(2a+b)(4a²−2ab+b²)
Answer:
27(2a+b)(4a²−2ab+b²)
Step-by-step explanation:
216a³+27b³
= 27(8a³+b³)
= (2a+b)(4a²−2ab+b²)
= 27(2a+b)(4a²−2ab+b²)